Match the column.
Column-I | Column-II |
(i) | [A] |
(ii) | [B] |
(iii) | [C] |
(iv) | [D] |
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
Ans.
(i) [C]
(ii) [B]
(iii) [D]
(iv) [A]
Sol. A → v = Kt
a = 
= K
B → v = Kt 2 a = 
= 2Kt
C → K 1 t → First part of graph
a = 
= K 1
v = K 2 → Second part of graph
a = 
= 0
D → v = v 0 e
– Kt a = 
= (–v 0 K) e
–Kt a = – a 0 e
–Kt a 0 = v 0 K
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle moving in a straight line covers half the distance with speed of 3 m/s . The other half …
A particle starts from rest. Its acceleration ( a ) versus time ( t ) is as shown in the figure. Th…
A car accelerates from rest at a constant rate for some time, after which it decelerates at a cons…
A stone dropped from a building of height and it reaches after seconds on earth. From the same bu…
A ball is projected upwards from a height above the surface of the earth with velocity . The time…
A particle is dropped vertically from rest from a height. The time taken by it to fall through succ…